Solving Unit Problems Made Easy: Understanding Electrical Power and Joules

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The discussion focuses on understanding electrical power units and their relationship to joules. Participants identify that electrical power is measured in watts, with the formula for power being P = V^2/R. They clarify that one joule is equivalent to one watt-second, leading to the conclusion that 1 A times 1 V equals 1 W, but not directly 1 J. Voltage is confirmed to be interchangeable with electric potential difference, emphasizing its role in the calculations. The conversation highlights the importance of grasping these fundamental concepts in electrical engineering.
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Homework Statement



which is unit is a unit of electrical power
v/a a/ohms a^2/ohm v^2/ohm
which unit is= to one joule
v/m a(x)v v/c c(x)v
thanks- the x is a multiplication sign

Homework Equations





The Attempt at a Solution

 
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hi jfio93! :wink:

tell us what you think, and then we'll comment :smile:
 
for the first one i put v^2/ohms cause power v^2/R
the second one i put a times v
 
hi jfio93! :smile:
jfio93 said:
for the first one i put v^2/ohms cause power v^2/R

yes, 1 V2Ω-1 = 1 W, which is power :smile:
the second one i put a times v

1 A times 1 V is 1 W … that's not 1 J :redface:

hint: what is the definition of voltage? :wink:​
 
well can't it be used interchangeably as potential difference so i no v is there i would say v/c
 
(just got up :zzz: …)
jfio93 said:
well can't it be used interchangeably as potential difference

yes, voltage difference and electric potential difference are the same :smile:

and electric potential is defined as … ? :wink:​
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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