Solving Wheel and Forces Homework: Show Weight of Wheel is 180N

  • Thread starter Thread starter aurao2003
  • Start date Start date
  • Tags Tags
    Forces Wheel
AI Thread Summary
To solve the problem, the key is to apply the principle of moments. The wheel's weight can be determined by balancing the moments around point C, where the wheel contacts the kerb. Given the height of the kerb and the radius of the wheel, the horizontal force of 240N creates a moment that must equal the moment created by the weight of the wheel. By calculating the distances involved, it can be shown that the weight of the wheel is indeed 180N. Understanding the relationship between force, distance, and moments is crucial for solving this type of physics problem.
aurao2003
Messages
122
Reaction score
0

Homework Statement


Hi
I am not sure about this question. Can anyone help?

It states this way:
A wheel of radius 0.5m rests on a level at a point C and makes contact with the edge E of a kerb of height 0.2m. A horizontal force of 240N, applied through the axle of the wheel at X, is required just to move the wheel over the kerb. Show that the weight of the wheel is 180N.





Homework Equations


Moment = Perpendicular force x distance



The Attempt at a Solution


I was thinking of taking moments but not even sure how to begin.
 
Physics news on Phys.org
I have replied to this on TSR.
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Force exerted on counter-rotating wheels by a tennis ball
Replies
44
Views
6K
Refresher on pulling weight on a wheel
Replies
12
Views
3K
Force needed to push a trolley onto sidewalk
Replies
7
Views
2K
Accelerating a car including the moment of inertia of the wheels
Replies
33
Views
11K
[High school physics] Wheel touching a kerb. What are the forces on the wheel?
Replies
4
Views
6K
What is the Output Force of a Wheel Axle?
Replies
14
Views
2K
Descending mass on rope attached to wheel
Replies
13
Views
7K
Forces of Rolling Homework: Find Frictional Force on Wheel
Replies
10
Views
2K
How Much Force is Needed to Lift a Wheel Over an Obstacle?
Replies
2
Views
5K
Car on a ramp with uneven weight distribution
Replies
3
Views
3K

Hot Threads

Recent Insights

Back
Top