Solving Work Done in Pushing Sled Up Snowy Incline

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SUMMARY

The discussion focuses on calculating the work done by a father pushing his daughter's sled up a snowy incline at a 15-degree angle. The total force exerted by the father is calculated to be 154.9N, derived from the frictional force and gravitational force acting on the sled. The work done, using the formula work = force × distance, is determined to be 2153J, with the sled moving a distance of 13.9m up the incline.

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Homework Statement



A father pushes horizontally on his daughter’s sled to move it up a snowy incline, If the sled moves up the hill with a constant velocity, how much work is done by the father in moving it from the bottom to the top of the hill? (angle of incline is 15 degrees
F + f(k) + mg = 0
F= -f(k)-mg
= -(-66.2N) - (-88.7N)
= 66.2N + 88.7N
= 154.9N

Work, w=fd
=154.9N * 13.9m
2153J




Homework Equations

work = force,f * Distance, d



The Attempt at a Solution



F + f(k) + mg = 0
F= -f(k)-mg
= -(-66.2N) - (-88.7N)
= 66.2N + 88.7N
= 154.9N

Work, w=fd
=154.9N * 13.9m
2153J
 
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foxproff said:
A father pushes horizontally on his daughter’s sled to move it up a snowy incline, If the sled moves up the hill with a constant velocity, how much work is done by the father in moving it from the bottom to the top of the hill? (angle of incline is 15 degrees

Is that the entire question?
 
yes
the plane makes an angle of 15 degrees with the horizontal
it has a height of 3.6m from the ground
thanks
 

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