Solving Work Done in Pushing Sled Up Snowy Incline

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The problem involves calculating the work done by a father pushing a sled up a 15-degree incline with constant velocity. The forces acting on the sled include kinetic friction and gravitational force, resulting in a total force of 154.9N required to move the sled. Using the work formula, the work done is calculated as 154.9N multiplied by the distance of 13.9m, yielding a total of 2153J. The incline's height is noted to be 3.6m, confirming the sled's movement against gravity. The solution effectively demonstrates the application of physics principles in calculating work done on an incline.
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Homework Statement



A father pushes horizontally on his daughter’s sled to move it up a snowy incline, If the sled moves up the hill with a constant velocity, how much work is done by the father in moving it from the bottom to the top of the hill? (angle of incline is 15 degrees
F + f(k) + mg = 0
F= -f(k)-mg
= -(-66.2N) - (-88.7N)
= 66.2N + 88.7N
= 154.9N

Work, w=fd
=154.9N * 13.9m
2153J




Homework Equations

work = force,f * Distance, d



The Attempt at a Solution



F + f(k) + mg = 0
F= -f(k)-mg
= -(-66.2N) - (-88.7N)
= 66.2N + 88.7N
= 154.9N

Work, w=fd
=154.9N * 13.9m
2153J
 
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foxproff said:
A father pushes horizontally on his daughter’s sled to move it up a snowy incline, If the sled moves up the hill with a constant velocity, how much work is done by the father in moving it from the bottom to the top of the hill? (angle of incline is 15 degrees

Is that the entire question?
 
yes
the plane makes an angle of 15 degrees with the horizontal
it has a height of 3.6m from the ground
thanks
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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