Solving Work Problem: Kinetic Energy of Toy Car After Braking

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The toy car initially has a kinetic energy of 6.4 J and experiences a frictional force of 0.63 N while sliding 62 cm. The work done by friction is calculated as W = 0.63 N * 0.62 m, resulting in 0.39 J of energy lost. To find the final kinetic energy, this energy loss is subtracted from the initial kinetic energy. Therefore, the kinetic energy after braking is 6.01 J. This demonstrates the application of work and energy principles in a practical scenario.
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The toy car is sliding with a kinetic energy of 6.4 J when it locks up its tires (obviously, the toy driver slammed on the toy brakes) and slides for 62 cm, while a frictional force of 0.63 N acts against it. What is the kinetic energy (in Joules) of the car after this frictional work is done?

I am not sure where to even start.
 
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Work = force * distance. How much energy is lost in braking, how much does it have left.
 
Since W=Force * distance then W = .63N * .62m, So W = .3906Nm with = .39 J. Would you then subtract the Jules? which would = 6.01 Joules
 
From conservation of energy you know that ke(start) = ke(end) + energy lost.
You know the ke at the start, you have found the energy lost - so ke at the end is easy.
 
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