Sound Intensity and Bird Watching

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Homework Help Overview

The discussion revolves around a problem related to sound intensity and distance, specifically concerning how far a bird watcher can be from a bird while still being able to hear its song. The problem involves calculations based on sound intensity levels and the inverse square law of sound propagation.

Discussion Character

  • Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to rearrange the intensity formula to find the distance at which the sound can still be heard. Some participants confirm the correctness of the approach but suggest re-evaluating the input values used in the calculations. Others point out a potential error in the intensity value for the threshold of hearing.

Discussion Status

The discussion is ongoing, with participants providing reassurance and suggesting that the original poster double-check their calculations. There is acknowledgment of a possible mistake in the intensity value used, which may have affected the outcome.

Contextual Notes

Participants are operating under the assumption that there are no reflections or absorption of sound, and they are working with specific intensity values for sound perception.

majormaaz
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Homework Statement


A bird watcher is hoping to add a particular song bird to the list of species she has seen. If a person, only 2.35 m from the bird, hears the sound with an intensity of 1.9 10-6 W/m2, how far could the bird watcher be from the bird and still hear it? Assume no reflections or absorption of the bird's sound and that the faintest sound that can be heard has an intensity of 10-12 W/m2.

Homework Equations


I2/I1 = (r1/r2)^2
I1 = 1.9e-6 W/m2
I2 = 10e-12 W/m2
r1 = 2.35 m
r2 = ?

The Attempt at a Solution


I rearranged the equation to solve for r2
I got r2 = √(I1 * r1^2/I2)
I plugged in the numbers and got 1024.34 meters
but the problem is saying that I did it wrong.
Is there another formula or did I just mess up somewhere in solving this?
Would appreciate help before Monday.
Thanks
 
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Hey,

See Intensity is inversely proportional to square of distance which is exactly what you used.

So your equations are correct.

Plug in the values again :-)
 
Last edited:
emailanmol said:
Hey,

See Intensity is inversely proportional to square of distance which is exactly what you used.

So your equations are correct.

Plug in the values again :-)

Thanks for the reassurance. However, I found out that my value for the Intensity of the threshold of hearing was wrong by a power. Thanks though
 
Oh.Lol.!

Yeah using 10^(-11) W/m^2 yields exactly the answer in your Post 1.
 
Last edited:

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