Sound intensity and ocean microphone

AI Thread Summary
The discussion centers on calculating the distance a porpoise can be from a microphone in the ocean while still being heard, given the microphone's sensitivity to sound intensity at 10.6 dB. The initial calculation mistakenly used an intensity value that was ten times too high, leading to an incorrect distance of 5.89E+3 meters. The correct intensity, derived from the dB formula, is 1.148E-11 W/m^2, resulting in a distance of approximately 1.87E+4 meters when applying the formula for intensity. The error was identified as a miscalculation of the intensity value used in the formula. Accurate calculations are crucial for determining sound detection ranges in underwater environments.
Corky
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The problem states:
A microphone in the ocean is sensitive to sounds emitted by popoises. To produce a usable signal , sound waves striking the microphone must have an intesity of 10.6 dB. If porpoises emit sound waves with a power of 0.0502 W, how far can a porpoise be from the microphone and still be heard? Disregard ansorbtion of sound waves by water.

I tried putting 10.6 decibels in the equation dB=10Log(I/Io)
and I solved for intensity to be 1.148E-10W/m^2

I then used that number in the I = P/4pi r^2 formula.
Solving for r I got 5.89E+3m.

But the right answer it the book is 1.87E+4
Can anyone tell me where I went wrong??
 
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Originally posted by Corky
A microphone in the ocean is sensitive to sounds emitted by popoises. To produce a usable signal , sound waves striking the microphone must have an intesity of 10.6 dB. If porpoises emit sound waves with a power of 0.0502 W, how far can a porpoise be from the microphone and still be heard? Disregard ansorbtion of sound waves by water.

10log(I/(10^-12)) = 10.6
log(I/(10^-12)) = 1.06
I/(10^-12) = 10^1.06
I = 1.148e-11

I = P/(4pi r^2)
r^2 = P/(4pi I)
r^2 = 0.0502/(4pi 1.148e-11)
r^2 = 3.4797e8
r = 18654m
r = 1.87e4

I think the error was in what you thought the value for I was. Your I is 10x as big as mine.
 
Nice thanks
 
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