Sound of Music - Closed Organ Pipe

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1. One closed organ pipe has a length of 2.40m.
a. What is the frequency of the note played by this pipe?
b. When a second pipe is played at the same time, a 1.40 Hz beat note is heard. By how much is the second pipe too long?




2. f = nv/2L (n = 1)
change of f = absolute value of f2 - f1




3. a. f = nv/2L (n = 1)
= 1(343)/2(2.4)
= 71.46 Hz

b. change of f = absolute value of f2 - f1
-1.4 = f2 - 71.46 1.4 = f2 - 71.46
f2 = 70.06, 72.86

f = nv/2L
70.06 = 343/2L 72.86 = 343/2L
140.12 L = 343 145.72 L = 343
L = 2.4479 L = 2.3538
2.4 - 2.4479 = 0.048 m
 

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