Sources of musical sound problem

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The discussion centers on calculating the lengths of two organ pipes based on their fundamental and harmonic frequencies. For organ pipe A, which has both ends open and a fundamental frequency of 450 Hz, the length is determined using the formula L = v/(2f), resulting in a length of 0.381 meters. For organ pipe B, which has one end open and its third harmonic matching the second harmonic of pipe A, the length is calculated using the relationship of wavelengths, yielding a length of 0.675 meters.

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Question: Organ pipe A, with both ends open, has a fundamental frequency of 450 Hz. The third harmonic of organ pipe B, with one end open, has the same frequency as the second harmonic of pipe A. Use 343 m/s for the speed of sound in air.
a)How long is pipe A?

b)How long is pipe B?

I found the length of pip a by f=v/2L, or 450=343/2L, L=343/900, which is correct.

I thought I could find the length of pipe B by setting an equality like this: (5v/4L)=(2v/2(.381)). I am pretty sure I did the algebra correctly but got an incorrect answer. Any help would be greatly appreciated...
 
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Fundamental frequency of pipe A = 450/s
First harmonic " = 900/s
Second harmonic " = 1350/s

Fundamental length of pipe B = 1/4 wavelength
|
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Length of pipe B for 3d harmonic = 7/4 wavelength

Solve just as you solved for the length of pipe A
 
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