(adsbygoogle = window.adsbygoogle || []).push({}); Please Help! - Specific Heat Problem...

I have been stuck for a while, it's online (Webassign), so it told me my answer was wrong.

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A 6.3x10^2 g sample of water at 90.0°C is mixed with 4.45x10^2 g of water at 22.0°C. Assume no heat loss to the surroundings. What is the final temperature of the mixture?

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The formula I know is right:

(cp)(m)(Tf- Ti) = (cp)(m)(Tf- Ti)

cp= spec. heat

m = mass

Tf = final Temp

Ti = initial Temp

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work:

converted grams into kilograms...

cp water, given

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(4186) (.630) (x-90) = (4186) (.445) (x-22)

774.41x = 196365.26

x = <<<it says it's wrong>>>

Where did I slip up?

Thanks.

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# Homework Help: - Specific Heat Problem

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