Specific slope for directional derivative?

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SUMMARY

The discussion centers on finding a direction vector where the rate of change of the function f(x,y) = (x^2)(y^3) + xy is 18 at the point (-1,2). Participants emphasize the importance of the gradient, specifically calculating ∇f, which was found to be <-14,11>. The user was advised to express one variable in terms of the other to resolve the two unknowns in the equations derived from the dot product of the direction vector and the gradient.

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glog
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Is there a direction where the rate of change is 18, at the point (-1,2) on the function f(x,y) = (x^2)(y^3)+xy?

So I found the gradient of this function, picked a random direction vector u = ( a / (a^2+b^2)^(1/2) , b / (a^2+b^2)^(1/2) ) and took the dot product, and set it to 18... however, I have one equation with two unknowns and no idea how to proceed.

Thank you.
 
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glog said:
Is there a direction where the rate of change is 18, at the point (-1,2) on the function f(x,y) = (x^2)(y^3)+xy?

So I found the gradient of this function, picked a random direction vector u = ( a / (a^2+b^2)^(1/2) , b / (a^2+b^2)^(1/2) ) and took the dot product, and set it to 18... however, I have one equation with two unknowns and no idea how to proceed.

Thank you.

don't do that mess..

just say u = <a,b> is unit vector
so, a^2+b^2 = 1 would be your second equation
and
<a,b>.del f = 18 your first equation

I found del f to be <-14,11>
this might be wrong, because I didn't recheck my work
 
It doesn't matter if you have 2 unknowns. You're interested in the direction, not the magnitude of the direction vector. Express either a or b in terms of the other and then normalise the vector (a,b)
 

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