mtjces said:Homework Statement
See picture.
Homework Equations
The Attempt at a Solution
I've decomposed F1 into F1x F1y and F1z..
F1x = 150 * sqrt 3
F1y = 150
F1z =150 * sqrt 2[
Now I'm stuck../QUOTE]
I don't know what sort of parallelogram you drew, but this is a 3-D kinda problem.mtjces said:Homework Statement
See picture.
Homework Equations
The Attempt at a Solution
I tried drawing a parallelogram, but it didn't help, so I'm stuck. I'd need an idea in the right direction, if possible.
SteamKing said:I don't know what sort of parallelogram you drew, but this is a 3-D kinda problem.
gneill said:I'm not seeing how you've accomplished your decomposition of F1. The magnitude of the vector comprised by those components would be about 367 N, which is larger than the given magnitude of F1. So you might want to re-think your method (whatever that was...).
The diagram is very helpful because it gives you the angles between F1 and each of the coordinate axes. This should make finding the projections of F1 on each of the axes easy to find.
For the Z component the angle was not 60 degrees. What does the diagram show it to be? Do you expect the Z-compoennt to be less than or greater than zero?mtjces said:F1z = cos 60 * 300N = 150N
F1x = cos 45 * 300N = 150*sqrt2 N
F1y = cos 60 * 300N = 150 N
Would this be correct?
You'll want to write a vector equation that expresses your desired result. Fix your F1 vector first though.I'm confused about the next step..
gneill said:For the Z component the angle was not 60 degrees. What does the diagram show it to be? Do you expect the Z-compoennt to be less than or greater than zero?
Check your value for cosine 45 degrees. A cosine should not be > 1.
You'll want to write a vector equation that expresses your desired result. Fix your F1 vector first though.
Yes, that looks right. The z-component is negative because the vector F1 is directed below the x-y plane.mtjces said:F1z = cos 120 * 300N = -0.5 * 300N = -150N (but how does that make sense?)
cos 45 = (√2)/2
so F1x = 300 N * cos 45 = 150 N * √2 = 150√2 N
F1y = cos 60 * 300N = 150 N
Is this right now?
gneill said:Yes, that looks right. The z-component is negative because the vector F1 is directed below the x-y plane.
gneill said:Yes, but sort out your component subscripts. You've listed F2z twice. It would help if you put them in standard order, too: x, y, z. Otherwise, I think you're there.
You don't know how to calculate the magnitude from the three force components?mtjces said:F2x = -150√2 N
F2y = 650 N
F2z = 150 N
How do I calculate F2?
mtjces said:F2x = -150√2 N
F2y = 650 N
F2z = 150 N
How do I calculate F2?
Sorry, messed up x:mtjces said:F2 = √((-150√2)^2 + 150^2 + 650^2) = 700 N
To calculate the angles of F2 I used:
cos x = (F2x/F2) = (-150√2 N / 700 N) ---> x = 72.36°
cos y = (F2y/F2) = (650N / 700 N) ---> y = 21.79°
cos z = (F2z/F2) = (150N / 700 N) ---> z = 77.63°
Correct?