Speed/Dist Question: Homework Solutions

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The discussion revolves around a physics homework problem involving the motion of a bag of candy released from a descending helicopter. For part (a), the initial speed of the bag is calculated as -30.4 m/s, but there is confusion regarding the units, as acceleration units were mistakenly used instead of speed. For part (b), participants emphasize the need to calculate the distance the bag falls in 3 seconds and compare it to the helicopter's position. The conversation highlights the importance of correctly applying physics equations and understanding unit conversions. Accurate calculations are essential for solving both parts of the problem effectively.
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Homework Statement


Santa arrives at the local mall by helicopter and, as the helicopter steadily descends at 1.0 m/s, he releases a bag of candy to the children waiting below. After 3 seconds:

a. what is the speed of the bag of candy?
b. how far is it below Santa’s helicopter?
c. What are the answers for parts (a) and (b) if Santa’s helicopter is departing, rising steadily at 1.0 m/s?


Homework Equations


For a. v=v0+gt

negative velocity and grav due to descend.

The Attempt at a Solution



a. -1 m/s+(-9.8m/s^2)(3s)
-1+(-29.4)
=-30.4 m/s^2

I need some assistance for the next step...
 
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Do you mean b for the next step? That looks right for the speed of the bag, but check your units. ##\frac{m}{s^{2}}## is a unit of acceleration, not speed. For b you want to calculate the distance the bag falls in that 3 seconds, and then compare that to the location of the helicopter also at 3 seconds.
 

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