1. The problem statement, all variables and given/known data A 1.5kg block is at rest on a table. The coefficient of friction between the block and the table is 0.15. A force of 6N is applied to the block for 2 seconds followed by a force of 1N (in the same direction) for 3s. (a)What is the speed of the block at the end (t=5)? (b)What is the total distance the block moves up to t=5? m=1.5kg v1=0m/s CofF=0.15 F1=6N t1=2s F2=1N t2=3s 2. Relevant equations I really don't even have an idea which formulas to use F=ma Ff=(coefficient of friction)(FN) Ek=(mv2)/2 W=FdcosA vf=vi+at d=vit+1/2at2 2ad=vf2-vi2 d=vt 3. The attempt at a solution Ff=CofF(FN)=0.15*1.5kg*9.8m/s2=2.205N Fnet=ma --> a=F/m --> a=(F1+F2-Ff)/m a=3.1967m/s2 ?????????????? I only (really) need help with part (a). I've tried about a dozen solutions and none of them have worked. I've been working on this question for hours, PLEASE help.