Speed of Free Electron Moving in Space

AI Thread Summary
The total energy of a free electron in space is expressed as E=1.5mc^2, where m is the electron's mass and c is the speed of light. The discussion highlights a misunderstanding in using classical kinetic energy equations, as they are only applicable when the electron's speed is much less than the speed of light. Instead, the proper relativistic kinetic energy equation should be used, which incorporates the Lorentz factor (gamma). The total energy combines the electron's kinetic energy and its rest mass energy, confirming that potential energy is zero for a free electron. The key takeaway is the importance of using relativistic equations for accurate calculations at high speeds.
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The total energy of a free electron moving through empty space is E=1.5mc^2, where m is the mass of the electron and c is the speed of light. What is this electron’s speed?

1. c (the speed of light)
2. 0.7453c
3. 0.8660c
4. 0.9428c
5. 0.9950c
6. 0.9999c


I thought since that Etotal = 1.5mc^2 then...

Etotal = KE = .5mv^2

1.5mc^2 = .5mv^2 and solve for v (masses would cancel which is what I was looking for)

What is wrong about this approach?
 
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Using KE = .5mv^2 is only good when v << c.

Hint:
E = \gamma m c^2
 
I believe that the proper relativistic kinetic energy equation would be

E_k = (\gamma - 1)mc^2

Or did you make that mistake on purpose, Doc Al?
 
oh shoot...i forgot about that. Do I need to use the non-approximated version of KE? (I can never remember it.. but I'm looking it up right now)
 
E is total energy, of course. :wink:

(There's no need to find kinetic energy.)
 
okay
 
so mc^2 would cancel out on both sides and I would be solving 1.5 = gamma right?
 
quickclick330 said:
so mc^2 would cancel out on both sides and I would be solving 1.5 = gamma right?
Yep. That's all you need to do.
 
ahh...got it, thank you :-)
 
  • #10
Oh, I get it... the total energy of the free electron is the sum of its kinetic energy and the energy from the mass-energy equivalence? The potential energy of the electron is zero, since it's free, right?

E_{total}= (\gamma - 1)mc^2 + mc^2
\ \ \ = \gamma mc^2

Is this so?
 
  • #11
kudoushinichi88 said:
Oh, I get it... the total energy of the free electron is the sum of its kinetic energy and the energy from the mass-energy equivalence? The potential energy of the electron is zero, since it's free, right?

E_{total}= (\gamma - 1)mc^2 + mc^2
\ \ \ = \gamma mc^2

Is this so?
Yep.
 
  • #12
Ah, thanks...
 
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