Speed when swinging from a rope?

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To determine Tarzan's speed at the bottom of a swing from a 23.8 m vine inclined at 36° from the vertical, potential energy at the top converts to kinetic energy at the bottom. For part (a), starting from rest, the speed can be calculated using the equation 1/2 mv^2 = mgh, where h is the height derived from basic trigonometry. For part (b), if starting with an initial speed of 2.22 m/s, the equation becomes 1/2 mv^2 + mgh = 1/2 mv^2, incorporating both initial kinetic energy and potential energy. The angle is crucial only for calculating the height, not for energy conservation. Understanding these principles allows for solving the speed at the bottom of the swing effectively.
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Tarzan swings on a 23.8 m long vine initially inclined at an angle of 36° from the vertical.

(a) What is his speed at the bottom of the swing if he starts from rest?
m/s

(b) What is his speed at the bottom of the swing if he starts with an initial speed of 2.22 m/s?
m/s

help please!
i have no idea how to do this ah!
 
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A)1/2 mv^2 = mgh
potential energy at the top = kinetic energy at the bottom of the pendulum.

B)1/2mv^2 + mgh = 1/2 mv^2
initial kinetic energy plus potential energy at the top = final kinetic energy at the bottom.
 
how do i factor in the angle?
 
the angle has nothing to do with the energy, only in finding the height.
 
how do i use it to find the height?
 
really basic trig.
 

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