Speedboat Acceleration Question

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SUMMARY

The discussion centers on a physics problem involving a speedboat decelerating from 31.0 m/s to reach a no-wake buoy marker 100 m away with a constant acceleration of -3.5 m/s². The participant initially struggles with the equations of motion but ultimately resolves the problem using the equation d = vit + (1/2)at². The conversation highlights the importance of articulating problems clearly, which aids in understanding and finding solutions.

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aquapod17
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Homework Statement


A speedboat moving at 31.0 m/s approaches a no-wake buoy marker 100 m ahead. The pilot slows the boat with a constant acceleration of -3.5 m/s2 by reducing the throttle.
(a) How long does it take the boat to reach the buoy?
______ s
(b) What is the velocity of the boat when it reaches the buoy?
______ m/s


Homework Equations


a = (vf-vi)/t
vf = vi + at
d = vit + (1/2)at^2
vf^2 = vi^2 + 2ad


The Attempt at a Solution



I keep getting an incorrect answer, but this is what I have been doing.
100 = 31t + (1/2)(-3.5)t^2
 
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Nevermind I got it! How do you delete threads. I feel really bad leaving this up here when I figured it out myself, but I don't know how to delete!
 
aquapod17 said:
Nevermind I got it! How do you delete threads. I feel really bad leaving this up here when I figured it out myself, but I don't know how to delete!

Hi aquapod17! :smile:

You can't delete, you can only do a "never mind" post :biggrin:

but it's ok … lots of members do that …

I think having to type it out for PF actually helps to make the question clearer! :smile:
 

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