Spherical capacitor and electric fields

  • #1
stompyourface
3
0
A spherical capacitor contains:
Region1: solid spherical conductor (radius=0.5mm, Q=7.4 micro coulombs)
Region2: surrounded by a dielectric material (er=1.8, radius extends to 1.2mm,
Region3: outer spherical non-conducting shell (variable charge per unit volume p = 5r, outer radius=2.0 mm)
Determine the electric field everywhere?

Homework Equations





Region 1: [1 r>r1] E = 0
Region 2: [r1 < r < r2] E = 7.4*10^-6 / (4 *∏ *1.8 * ε *r^2) = 3.71*10^4/r^2
Region 3: [r2 < r < r3] Q(r) = 5 ∏ (r4 − r40) = 2.19*10^-10 .
E = ( 7.4*10^-6 + 2.19*10^-10) / (4 ∏ εo) = 6.64*10^4
Total Electric Field = 3.71*10^4/r^2 + 6.64*10^4/r^2
Does this look right
 

Answers and Replies

Suggested for: Spherical capacitor and electric fields

Replies
9
Views
137
Replies
4
Views
374
Replies
19
Views
380
Replies
27
Views
902
Replies
54
Views
2K
  • Last Post
Replies
2
Views
454
Replies
17
Views
543
  • Last Post
Replies
4
Views
728
Replies
14
Views
448
Replies
4
Views
370
Top