Spherical coordinates rewrite help

Jbright1406
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Homework Statement


Let f(x,y,z) be a continuous function. To rewrite f(x,y,z) as a function of spherical coordinates, the conversion x-rcos(\theta), y=rsin(\theta), and z=rcos(\varphi). Suppose S is a region in 3 dimensions. How would you rewrite _{\int\int\int}s f(x,y,z)dV as the integral of a function in terms or r,\theta, and\varphi
Note the s by the integral should be a subscript

Homework Equations


Hint, may require a change of variable formula
3. The Attempt at a Solution

I attempted to plug in the conversion of x, y, and z, but i don't think this is what is needed. I believe it is more of a conceptual question. What should i do?, I am comfortable with the integration or deriving of the stuff, but am not sure what he is actually is asking. This isn't a homework problem to turn in, but something we were supposed to look at.
 
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Do you know of a function called the Jacobian function? Because you will need this to find out what dV changes to.


Also I think x=rcosθsinψ y=rsinθsinψ z=rcosψ
 
no, I've never seen jacobian's. I know the name and have heard them mentioned, but have never seen them

It says home work, buts it on the bottom of a test review, its not something to turn in, i can post the entire test review if you don't believe me, where it says it at the top of the page

here is a copy of the problem in case i typed it wrong
qxo0gp.jpg
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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