Splitting up exponential terms when integrating

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
2 replies · 6K views
leviathanX777
Messages
39
Reaction score
0
1. Relevant problem

integrate from 0 to infinity of r^2exp^(-r/a0)dr

Homework Equations



I'm also given; integral from 0 to infinity of x^nexp^-x dx = n!

The Attempt at a Solution



I'm just wondering if I can split up the exponential to make it look like this form. Eg;

integrate from 0 to infinity of (r^2e^(-r/a0)dr becomes; integrate from 0 to infinity of (r^2e^(-r)dr times integrate from 0 to infinity of (e^(1/a0)dr however I'm pretty sure when I split up the integral, the second term isn't correct. Can anyone help? I just don't want to integration by parts a lot of times. As there's two other terms with higher powers of r to go through.
 
on Phys.org
leviathanX777 said:
1. Relevant problem

integrate from 0 to infinity of r^2exp^(-r/a0)dr

Homework Equations



I'm also given; integral from 0 to infinity of x^nexp^-x dx = n!

The Attempt at a Solution



I'm just wondering if I can split up the exponential to make it look like this form. Eg;

integrate from 0 to infinity of (r^2e^(-r/a0)dr becomes; integrate from 0 to infinity of (r^2e^(-r)dr times integrate from 0 to infinity of (e^(1/a0)dr however I'm pretty sure when I split up the integral, the second term isn't correct. Can anyone help? I just don't want to integration by parts a lot of times. As there's two other terms with higher powers of r to go through.
It looks like you are thinking that e-r/a = e-r * e1/a, which is not true. Review the properties of exponents. This wikipedia page has a summary.

The fastest approach to your integral, I believe, is by integration by parts. One application should get you to a form similar to the one you show in your relevant equations.
 
I did it already using integration by parts. First time I did it didn't yield something similar to the hint I was given. Had to do integration by parts twice and the exponential was still divided by ao all the way through.