Spring and Hammer Problem: Calculate Motion w/m, k, J, t

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The Spring and Hammer problem involves a mass m at rest on a spring with spring constant k, which receives an impulse J at t = 0. The correct approach to model the force from the impulse is to use Dirac's delta function and solve the problem using Laplace Transforms. After the impulse, the mass has an initial velocity of v_{0} = J/m. The differential equation governing the motion is -kx = m\ddot{x}, with initial conditions x(0) = 0 and \dot{x}(0) = J/m. This method effectively addresses the dynamics of the system following the impulse.
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Problem: A mass m is at rest on the end of a spring of spring constant k. At t = 0 it is given an impulse J by a hammer. Write the formula for the subsequent motion in terms of m, k, J, and t.

Would ma = -kx + J/t be an acceptable answer?
 
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No, it is not!
The force associated by impulse J should be modeled by Dirac's delta function; solve the problem with Laplace Transforms.
 
Last edited:
Please note that the problem is from a general physics textbook. Assume as many simplifying assumptions as possible.
 
In that case, solve it as follows:
Just after the impulse J, the mass has an initial velocity v_{0}=\frac{J}{m}
In the subsequent problem, your diffferential equation is:
-kx=m\ddot{x}
whereas initial conditions are:
x(0)=0,\dot{x}(0)=\frac{J}{m}
 
Last edited:
Hmm...Why didn't I think of that? I guess that does it for that problem. Thanks.
 
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