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myk127
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Homework Statement
A 2.0 kg block is placed on top of a spring which is compressed 0.5 m. The spring constant of the spring is 2.50 N/cm. when the block is released, find (a) the velocity at which the block leaves the spring (b) the velocity of the block when it has risen 1.00 m (c) the maximum height that the block can reach.
Homework Equations
The Attempt at a Solution
a) I tried using the formula W = ΔKE + ΔPE + ΔPEe
since there's no other work done W = 0. I canceled ΔKE because there's no motion in the object at the beggining and at the highest point. then I canceled PE1 because there's no height yet then I canceled PEe2 because it not in contact with the spring anymore. then my formula looked like this:
PEe2 = PE1 -----> ½kx² = mgh
how can i find the initial Velocity with the formula I got? pls tell me I did something wrong or if I forgot any thing.