- #1
Jamboree
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I feel like I must be missing something here. I think I'm following the right steps, yet my answer doesn't match one of the choices.
A Mass of 3.0kg is hung from a spring, causing it to stretch 12 cm at equilibrium. The 3.0kg mass is then replaced by a 4.0kg mass and the new block is released from the unstretched position. How far will the 4.0kg mass block fall before its direction is reversed?
a) 9 cm
b) 18 cm
c) 24 cm
d) 32 cm
e) 48 cm
Spring Constant-
k= F/x
First, I found the force of the 3kg block.
F= 3 * 9.8 = 29.4N
Next, I found the spring constant K
K= F/x[distance] = 29.4/.12m= 245
I Worked backwards to find the distance traveled by the 4kg block, like this.
K=F/x
245= (4*9.8)/x
x=.16m = 16 cm
Which is not one of the options. Where have I gone wrong?
Thanks for any help, it is much appreciated.
Homework Statement
A Mass of 3.0kg is hung from a spring, causing it to stretch 12 cm at equilibrium. The 3.0kg mass is then replaced by a 4.0kg mass and the new block is released from the unstretched position. How far will the 4.0kg mass block fall before its direction is reversed?
a) 9 cm
b) 18 cm
c) 24 cm
d) 32 cm
e) 48 cm
Homework Equations
Spring Constant-
k= F/x
The Attempt at a Solution
First, I found the force of the 3kg block.
F= 3 * 9.8 = 29.4N
Next, I found the spring constant K
K= F/x[distance] = 29.4/.12m= 245
I Worked backwards to find the distance traveled by the 4kg block, like this.
K=F/x
245= (4*9.8)/x
x=.16m = 16 cm
Which is not one of the options. Where have I gone wrong?
Thanks for any help, it is much appreciated.