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## Homework Statement

When a mass is attached to a vertical spring, the spring is stretched a distance d. The mass is then pulled down from this position and released. It undergoes 57 oscillations in 39.0 s. What was the distance d?

## Homework Equations

F=-Kx

F=mg

T=2pi*sqrt(K/m)

## The Attempt at a Solution

I started by putting the first two equations equal.

[itex] -K x= m g [/itex]

Solving for x you get

[itex] [1] (m g) /-K= x [/itex]

Then I solved for m/K in the third equation.

[itex][2] (2 π / T )^2=m / K [/itex]

Then I solved for osc/s which came to be 1.46 osc/s

Substituting {2} for {1} I came up with

[itex] g*(- 2 π/ T)^2= x [/itex] BUt i feel like this equation is wrong. Any help?