1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Spring truck problem

  1. Apr 10, 2005 #1
    2. A spring from the truck is found not to conform to Hooke’s law. The force law for this spring is
    found to be:
    F = – k1x – k2 x^2
    where k1 = 52.8 N.m-1; k2 = 38.4 N.m-2.
    a) Compute the work required to stretch the spring from x = 0.500 m to x = 1.00 m.
    b) With one end of the spring fixed, a particle of mass 2.17 kg is attached to the other end of the
    spring when it is extended by an amount x = 1.00 m. If the particle is then released from rest,
    compute its speed at the instant the spring has returned to the configuration in which the extension
    is x = 0.500 m.
    c) Is the force exerted by the spring conservative or nonconservative? Explain your answer.

    Ok, for a)

    sub in the numbers for x = 1m and you get -91.2 N
    sub in the numbers for x= .5m and you get - 36 N

    So force is 127.2 N when the spring is stretched from .5 to 1m?

    As W = F*x, do i just plug in x=.5m and F = 127.2 N?

    Cheers
     
  2. jcsd
  3. Apr 10, 2005 #2
    In a and b. Calculate the energy in x = 0,5 and x = 1,00. You can't do a with the simple W = Fs because F is changeable.
     
  4. Apr 11, 2005 #3
    So you have to integrate?
     
  5. Apr 11, 2005 #4
    Yeah, I think so,

    Work done = Integral F.dx : Limits of Integraton are from x = 0.5 to x = 1.00
     
  6. Apr 11, 2005 #5
    Cheers :smile:
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?



Similar Discussions: Spring truck problem
  1. Truck problem (Replies: 1)

  2. Power-Truck Problem (Replies: 7)

Loading...