Spur Gear, Friction and Energy Loss

AI Thread Summary
To analyze friction losses in a spur gear drive, one must first estimate the frictional force acting on the component. This force can be used to calculate the additional torque required from the engine to counteract these losses. The power lost due to friction can be expressed as the product of the frictional force and the velocity, leading to the equation for energy lost over time. If the angular velocity remains constant, the energy lost simplifies to a straightforward formula involving the frictional force, radius, angular velocity, and time. Understanding these calculations is crucial for optimizing the efficiency of robotic components.
619313
Messages
8
Reaction score
0
For an analysis of a robot component: a Spur gear drive/train.

How can I account for friction losses?
I can calculate the torque, with neglecting friction.


And what about the change in energy?
I know power = torque*angular velocity
 
Engineering news on Phys.org
first you need a way to estimate the frictional force F on part.

this frictional force, acting on a shaft of radius R will exert a torque FxR.

You can tell your engine to exert that much more torque and it will cancel out the frictional losses.

If you want to calculate the energy lost:
Power lost = F x velocity
Power lost = F x (R * angular velocity)
Power lost = ( F x R ) * angular velocity

to find the energy lost, you would have to integrate this function. If the angular velocity is constant and the motor is run for a time t, the equation simplifies to:

Energy lost = ( F x R ) * angular velocity * t
 
Posted June 2024 - 15 years after starting this class. I have learned a whole lot. To get to the short course on making your stock car, late model, hobby stock E-mod handle, look at the index below. Read all posts on Roll Center, Jacking effect and Why does car drive straight to the wall when I gas it? Also read You really have two race cars. This will cover 90% of problems you have. Simply put, the car pushes going in and is loose coming out. You do not have enuff downforce on the right...
Thread 'Physics of Stretch: What pressure does a band apply on a cylinder?'
Scenario 1 (figure 1) A continuous loop of elastic material is stretched around two metal bars. The top bar is attached to a load cell that reads force. The lower bar can be moved downwards to stretch the elastic material. The lower bar is moved downwards until the two bars are 1190mm apart, stretching the elastic material. The bars are 5mm thick, so the total internal loop length is 1200mm (1190mm + 5mm + 5mm). At this level of stretch, the load cell reads 45N tensile force. Key numbers...
I'm trying to decide what size and type of galvanized steel I need for 2 cantilever extensions. The cantilever is 5 ft. The space between the two cantilever arms is a 17 ft Gap the center 7 ft of the 17 ft Gap we'll need to Bear approximately 17,000 lb spread evenly from the front of the cantilever to the back of the cantilever over 5 ft. I will put support beams across these cantilever arms to support the load evenly

Similar threads

Back
Top