Square Loop of Copper Wire Falls out of

Click For Summary
SUMMARY

The discussion centers on calculating the terminal velocity of a square loop of copper wire falling out of a magnetic field with a magnetic flux density (B) of 1.2T, a side length (a) of 5cm, and a radius (r) of 1mm. The key insight is that at terminal velocity, the net acceleration is zero, meaning the magnetic force must balance the gravitational force acting on the loop. Participants emphasize the importance of recognizing this balance to solve the problem effectively.

PREREQUISITES
  • Understanding of terminal velocity concepts
  • Knowledge of magnetic forces and their calculations
  • Familiarity with gravitational force equations
  • Basic physics equations, particularly kinematics
NEXT STEPS
  • Study the principles of magnetic force on conductors in magnetic fields
  • Learn how to calculate gravitational force on objects
  • Explore the concept of terminal velocity in fluid dynamics
  • Review kinematic equations and their applications in physics problems
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone interested in understanding the dynamics of objects in magnetic fields, particularly in relation to terminal velocity calculations.

ryguy7272
Messages
2
Reaction score
0

Homework Statement


I am stuck on a HW problem. A square loop of copper wire falls out of a side 'a' and radius 'r' falls outside of a magnetic field 'B'. How does one find the terminal velocity?
B = 1.2T
a = 5cm
r = 1mm

Please help me set up this problem so I can solve it and figure out what is going on!

Thanks,
Ryan---


Homework Equations


Perhaps...
vf = vi + at


The Attempt at a Solution

 
Physics news on Phys.org
Welcome to PF!

ryguy7272 said:
I am stuck on a HW problem. A square loop of copper wire falls out of a side 'a' and radius 'r' falls outside of a magnetic field 'B'. How does one find the terminal velocity?

Perhaps...
vf = vi + at

Hi Ryan! Welcome to PF! :smile:

Forget about acceleration!

Terminal velocity means that the acceleration is zero!

So just balance the magnetic force against gravity. :wink:
 
Ah! Failed to see the obvious.
Thanks!

Regards,
Ryan---
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
Replies
2
Views
2K
Replies
5
Views
3K
Replies
5
Views
2K
Replies
4
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
Replies
6
Views
2K
  • · Replies 3 ·
Replies
3
Views
5K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 10 ·
Replies
10
Views
5K