# Static and Kinetic Friction Forces (Finding Net Force)

## Homework Statement

The coefficient of static friction between a block and a horizontal floor is 0.414, while the coefficient of kinetic friction is 0.138. The mass of the block is 5.24 kg. A horizontal force is applied to the block and slowly increased. What is the value of the applied horizontal force at the instant that the block starts to slide?

b) What is the net force on the block after it starts to slide?

F=uN

## The Attempt at a Solution

a)Okay, so the answer to the first part is 21.3 N.

F = uN where us is .414 and N is mg.

b) I don't get how to find the net force. So the mg and Normal force cancel out, so I calculated the horizontal forces using F=uN. I subtracted the static force from the kinetic force and the answer was wrong. What am I doing wrong?

Related Introductory Physics Homework Help News on Phys.org
Delphi51
Homework Helper
No information is given about the acceleration, which affects the answer. Some assumption must be made. You could assume the object is moving in uniform motion with no acceleration, in which case the net force is zero from F = ma. However, I suspect you are supposed to assume that the force you found in part (a) continues to be applied. Since the friction force is now reduced, the object will accelerate horizontally so there is a nonzero net force acting on it. Just add up the horizontal forces (not including F = ma which tells what acceleration the net force causes). The vertical forces add to zero as you said.

Yea what I'm not sure about is what forces they are.

Is it the static Friction force + the Kinetic Friction force? I really don't know what the horizontal forces are

bump sry but its due tomorrow

doesn't anyone know this?

bump bump bump

nvn
Homework Helper
FAJISTE: For part (b), change the plus sign in post 3 to a minus sign.

Yeah i tried that too and the answer was wrong :(

nvn