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- Thread starter benny1993
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BvU

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What is the direction of F

- #3

benny1993

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And about the direction of F(p), I assumed it would be horizontal since the beam is in static equilibrium while remaining horizontally.

- #4

Chestermiller

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Why not just write the moment balance simply as $$(120)(6)=T_y(12)$$

- #5

benny1993

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Wouldn't the answer still be the same?Why not just write the moment balance simply as $$(120)(6)=T_y(12)$$

- #6

BvU

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Assumption is unfounded.I assumed it would be horizontal since the beam is in static equilibrium

- #7

benny1993

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Then what would be the correct answer?Assumption is unfounded.

- #8

Chestermiller

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Yes, but wouldn’t be simpler? This would also allow you to immediately determine the vertical reaction force component at the pin.Wouldn't the answer still be the same?

- #9

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But you have the 75 lb right there in your calculations.

The question is*what is the magnitude of the force*, not *what is the horizontal component of the force*.

The question is

Last edited:

- #10

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Not exactly. The 75lb found in post #1 is for the tension in the cable. However, there is a neat way of seeing that the reaction at the hinge must have the same magnitude.But you have the 75 lb right there in your calculations.

The question iswhat is the magnitude of the force, notwhat is the horizontal component of the force.

Easily falsified. Consider moments about the tip of the beam.And about the direction of F(p), I assumed it would be horizontal

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