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Statics Homework help -- find tension
1. In Figure P4.111 determine the tensions in cables BC and BE. Neglect the weights of all members and assume that the support at A is a ball-and-socket joint. The 5200-N force has no x component.
(picture is attached below)2. \Sigma Fx = 0
\Sigma Fy = 0
\Sigma Fz = 0
\Sigma MD = 0
Okay so I figured out the angles of the cables and did the sum of the forces.
I had trouble figuring out the sum of the moments.
Here is what I have so far:
\Sigma Fx = 0 --> Ax + T1*cos(26.6) = 0
\Sigma Fy = 0 --> Ay + T1*sin(26.6) + T2*cos(18.4) + 5200*cos(22.6)= 0
\Sigma Fz = 0 --> Az + T2*sin(18.4) + 5200*sin(22.6) = 0
T1 is the cable from B to E
T2 is the cable from B to C
Anything you guys can do to help would be much appreciated, thanks!
1. In Figure P4.111 determine the tensions in cables BC and BE. Neglect the weights of all members and assume that the support at A is a ball-and-socket joint. The 5200-N force has no x component.
(picture is attached below)2. \Sigma Fx = 0
\Sigma Fy = 0
\Sigma Fz = 0
\Sigma MD = 0
The Attempt at a Solution
Okay so I figured out the angles of the cables and did the sum of the forces.
I had trouble figuring out the sum of the moments.
Here is what I have so far:
\Sigma Fx = 0 --> Ax + T1*cos(26.6) = 0
\Sigma Fy = 0 --> Ay + T1*sin(26.6) + T2*cos(18.4) + 5200*cos(22.6)= 0
\Sigma Fz = 0 --> Az + T2*sin(18.4) + 5200*sin(22.6) = 0
T1 is the cable from B to E
T2 is the cable from B to C
Anything you guys can do to help would be much appreciated, thanks!