Statics struss tension/compression

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In summary, the conversation discusses the determination of tension and compression in different parts of a structure, specifically in the case of DG, DE, and HG. The individual asking the question is seeking clarification on how to determine the direction of tension and compression and whether there is a specific procedure to follow. The response advises making assumptions consistent with Newton's 3rd law and limiting the number of assumptions made. It also emphasizes the importance of calculating support reactions first and considering the direction of forces to determine the direction of tension and compression.
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xzibition8612
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Why is DG, DE in tension while HG is in compression according to the FBD? How did the book determine this? Do you just randomly guess tension/compression and then do the calculations and see if you get a positive/negative number? Is there a set procedure? Thanks.
 

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It's ok to make assumptions, consistent with Newtons 3rd law, but limit the number of assumptions you make or else the plus and minus sign will devour you. I notice that the solution shows Ax pointing right, when obviously it must point left, so don't assume when you don't have to. Always calculate support reactions first, numerically, that's a big help. When you look at the right side cut section, since R points up, producing ccw moment about G, then Fde must point inward toward the joint, to produce a cw moment about G . Fde is compression by the way, since it points toward joint . Forces pulling away from joint are tensile.
 

1. What is the difference between tension and compression in statics struss?

Tension and compression are both forms of mechanical stress that occur in structural systems like trusses. Tension is a type of stress that occurs when a force pulls on a material, causing it to elongate. Compression, on the other hand, occurs when a force pushes or squeezes on a material, causing it to shorten or compact. In statics strusses, tension and compression can both be present depending on the direction and magnitude of the forces acting on the structure.

2. How do you calculate tension and compression forces in a statics struss?

In order to calculate tension and compression forces in a statics struss, you need to use the principles of equilibrium. This means that the sum of all forces acting on the struss must be equal to zero, and the sum of all moments (or torques) must also be equal to zero. By setting up and solving equations based on these principles, you can determine the tension and compression forces at each joint in the struss.

3. What factors can affect tension and compression forces in a statics struss?

There are several factors that can affect tension and compression forces in a statics struss. These include the direction and magnitude of external forces acting on the struss, the geometry and material properties of the struss, and the presence of any internal forces (such as reactions at supports or internal axial loads). Changes in any of these factors can result in changes to the tension and compression forces in the struss.

4. How can you ensure that a statics struss is stable under tension and compression forces?

In order to ensure that a statics struss is stable under tension and compression forces, it is important to carefully design and analyze the structure. This includes considering the direction and magnitude of external forces, selecting appropriate materials and cross-sectional shapes, and ensuring that the forces at each joint are in equilibrium. Additionally, proper bracing and support systems can help to distribute and balance the tension and compression forces in the struss.

5. How does the concept of stress affect tension and compression in a statics struss?

The concept of stress is closely related to tension and compression in a statics struss. Stress is a measure of the internal forces that act on a material, and it is directly related to the amount of tension or compression that a material is experiencing. In a statics struss, high levels of stress in a certain member can indicate that it is experiencing a high amount of tension or compression, which can help in the design and analysis process.

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