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Stationary motorcycle speeding up to a moving car

  1. Dec 14, 2007 #1
    Hi everyone

    I was wondering if anybody knows how to do the questions that involve a moving car and a motorcycle speeding up from rest to overtake the car. The questions give you a velocity/time graph of the movement of both the car and the motorcycle to work with. the questions ask at what time does the motorcycle overtakes the car.
     
  2. jcsd
  3. Dec 14, 2007 #2

    rl.bhat

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    Draw velocity/time graph of the movement of both the car and the motorcycle. If you find a point of intersection, then the motercycle overtakes the car and the point of intersection gives you the time.
     
  4. Dec 14, 2007 #3
    But wouldn't the intersection on a velocity/time graph be the point where both vehicles are moving at the same speed as opposed to being at an equal position from the start?
     
  5. Dec 15, 2007 #4
    i'd say integrate (find area under curve of) the V vs T graph to find D vs T, then see where their distances match up, and find the time when this occurs.
     
  6. Dec 15, 2007 #5

    rl.bhat

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    When you start the clock, at t = 0, velocity of the motercycle will be zero and the car will have some velocity . They need not start from the same point but must be on the same line. To overtake the car motercycle must have larger acceleration. And they will meet when the realtive velocity of car and motercycle is zero.
     
  7. Dec 15, 2007 #6
    If you haven't dealt with relative velocities yet (which I'm guessing you haven't) I'd approach the problem in lieu of kinematics. You can find the acceleration of each object (dv/dt) and the initial velocities from the individual graphs. Then just use your kinematic equations to find when (or where) the objects meet up.
     
  8. Dec 15, 2007 #7
    Do you know if there is a specific, more mathematical way of doing this sort of problem?
     
  9. Dec 15, 2007 #8

    rl.bhat

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    Find the relative velocity of car and motercycle. (Vc - Vm) when t = 0. When motercycle ovetakes the car relative velocity = 0. To solve the problem you must know one more quantity, the acceleration of the motercycle.
     
  10. Dec 15, 2007 #9

    cristo

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    Of course, this method will only work for uniform acceleration, which the OP does not specify.
     
  11. Dec 15, 2007 #10
    No, the graphs do not involves uniform accelerations.

    The car is moving at the same velocity throughout and motorcycle accelerates from rest to a certain point, changes its acceleration and then travels at a constant velocity, which is higher that the car's.
     
  12. Dec 16, 2007 #11
    Yea I would suggest finding the area under the curve of both graphs (velocities of moto and car), and making a new D vs T graph. Plot both displacements on the same axis and see where they intersect.
     
  13. Dec 16, 2007 #12
    Integrate the velocity functions of both the car and the motorcycle to get started.
     
  14. Dec 16, 2007 #13
    System of equations....
     
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