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Homework Statement
Consider a system consists of two subsystem A and A' in which A contains 3 spins and A' contains 2 spins. Suppose that, when the systems A and A' are initially separated from each other, measurements show the total magnetic moment of A to be - 3{\mu _0} and the total magnetic moment of A' to be + 4{\mu _0}. The systems are now placed in thermal contact with each other and are allowed to exchange energy until the final equilibrium situation has been reached. Under these conditions calculate:
(a) The probability P(M) that the total magnetic moment of A assumes anyone of its possible values M.
Homework Equations
Basic statistic and probability tools.
The Attempt at a Solution
The question implies that each of the spin in A has magnetic moment {\mu _0} while A' has 2{\mu _0}.
Originally, the system has the spin arrangement like this:
--- ++
where - means spin down and vice versa.
After they are in contact, they can have the following possibility.
--- ++ - 3{\mu _0}
--+ -+ - {\mu _0}
-+- -+ - {\mu _0}
+-- -+ - {\mu _0}
+-- +- - {\mu _0}
+-+ -- {\mu _0}
++- -- {\mu _0}
--+ +- - {\mu _0}
-++ -- {\mu _0}
-+- +- - {\mu _0}
So P( - 3{\mu _0}) = \frac{1}{{10}}, P( - {\mu _0}) = \frac{6}{{10}}, P({\mu _0}) = \frac{3}{{10}}.
But the answer is P({\mu _0}) = \frac{6}{7}, P( - 3{\mu _0}) = \frac{1}{7}.
What's wrong?