Statistics of charged beads in electric field

AI Thread Summary
The discussion focuses on calculating the average length of a string of charged beads in an electric field, considering the effects of the charge on the last bead. The energy of the system is influenced by the alignment of the rods with the field, leading to different energy states for aligned and anti-aligned configurations. The potential energy of the charged bead is expressed in terms of its position and the electric field, which affects the orientation of the rods. The partition function is derived to determine the probabilities of different rod alignments, ultimately allowing for the calculation of the average length of the string. The conversation emphasizes the importance of correctly defining energy states and their contributions to the overall system.
Beer-monster
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Homework Statement



Consider a string of N beads connected by N-1 rigid rods of length l. The system is considered as one-dimensional with rods only being aligned either up or down. The string is immersed in a fluid at temperature T and first bead is fixed at the origin y=0. A constant electric field is applied in the positive y direction.

What is the average length of the string if only the last bead holds a charge q.


Homework Equations



\sum\frac{e^{-\beta E}}{Z}


The Attempt at a Solution



I'm a little unsure about how to consider the effects of the charged bead in the field.

My thoughts in general were to consider the rods in two states, either aligned with or against the field. If aligned with the field the energy is negative -eEl. If aligned with the field the energy is positive +eEl. By considering these states I hope to determine the probability of a rod being aligned with/against field and from that determine the expectation value of the length.

One one hand if only the end bead is charged only that bead will show a preferential alignment and the rest will be random.

On the other hand; if the Nth bead feels a force due to the applied field it will also apply a force to the N-1th bead, which will apply the force to the N-2th bead etc. In that way the work will be applied to all of the rods so the energy shift will apply to all beads.

Which is right? Or am I completely off-base?
 
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For the partition function, you need an expression for the energy of the system for each possible state of the system. A state of the system is a specification of the orientations of the individual rods. The energy of the system is equal to the electrical potential energy of the charged bead and that’s determined by the charged bead’s y coordinate, yN.

If you knew the orientations of all the rods, how could you calculate yN? It might be helpful to introduce a variable for each rod to denote it’s orientation, say sk for the kth rod. Let sk = 1 or -1 for the rod being parallel or antiparallel to the field, respectively. Can you express yN in terms of the sk variables and the length of each rod?

How would you express the electrical potential energy of the system in terms of yN?
 
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If we define Sk as +/-1 depending on if the rods are aligned with the field the length of the string would be:

y_{N}=\sum_{N} S_{k}l where l is the length of a rod.

In the absence of an initial coordinate for the Nth bead I would express the potential energy of due to the field as \epsilon = q_{N}Ey_{N}

Thus the partition function per rod would be

Z = \sum^{+1}_{S_{k}=-1} e^{\beta q_{N}E\sum_{N} S_{k}l}

Using this I can determine the probability and thus the average number of a rod being aligned with or against the field and sum to make the average length.
 
Beer-monster said:
If we define Sk as +/-1 depending on if the rods are aligned with the field the length of the string would be:

y_{N}=\sum_{N} S_{k}l where l is the length of a rod.
Yes. The sum is over k from 1 to N-1?
In the absence of an initial coordinate for the Nth bead I would express the potential energy of due to the field as \epsilon = q_{N}Ey_{N}

The potential energy of a (positive) charge decreases as the charge moves in the direction of the field. So, the sign is not correct for the energy.
Thus the partition function per rod would be

Z = \sum^{+1}_{S_{k}=-1} e^{\beta q_{N}E\sum_{N} S_{k}l}

Here, the sign of the argument of the exponential is correct!
Using this I can determine the probability and thus the average number of a rod being aligned with or against the field and sum to make the average length.

Yes.
 
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