Steady State Sinusoidal using Nodal Analysis

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Discussion Overview

The discussion revolves around a homework problem involving steady state sinusoidal analysis using nodal analysis. Participants are examining the correctness of their solutions in relation to a provided answer key, which appears to have discrepancies due to a potential error in the problem statement.

Discussion Character

  • Homework-related

Main Points Raised

  • One participant notes that the problem statement was incorrectly printed in the book, suggesting the source should be 100t instead of 80t.
  • Another participant confirms the equations used for nodal analysis appear correct and advises double-checking the calculator values.
  • A third participant agrees with the calculations and speculates that the problem may have been modified without updating the answer key.
  • A question is raised about the origin of the problem, leading to clarification that it is from the US.

Areas of Agreement / Disagreement

Participants generally agree on the correctness of the equations used for nodal analysis, but there is uncertainty regarding the accuracy of the provided solutions and the problem statement itself. The discussion remains unresolved regarding the exact source of the discrepancies.

Contextual Notes

There are limitations related to the potential modification of the problem statement and the answer key not being updated, which may affect the validity of the solutions provided.

Joshb60796
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Homework Statement


problem 47.jpg
[/B]
The photo included provides the problem but the professor stated that the right side source is supposed to be 100t and not 80t. The problem wasn't printed correctly in the book so I assume the solution wasn't either. The solution via the book is v1=2.56cos(100t+139.2°), v2=4.35cos(100t+138.3°)

Homework Equations


Rectangular to Polar Notation
Polar to Rectangular Notation
Ohms Law
Nodal Analysis
Kirchhoff's Current Law

The Attempt at a Solution


I used Nodal Analysis
v1: ((v1)/1∠90°)+((v1)/2)+(((v1)-(v2))/4.55∠-90°)+(((v1)-(v2))/3) - (3∠62°)=0
v2: 2+((v2)/(2.13∠-90°))+((v2)/5)+(((v2)-(v1))/4.55∠-90°)+(((v1)-(v2))/3)=0
plugging that into the calculator and solving gives
v1=2.84∠131.12°
v2=3.56∠122.15°
Which is NOT the book solution. Please tell me if I did this correctly.
 
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Your equations look correct, so just double check the values you obtained from the calculator.
 
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I can confirm that the values look good, too.

I suppose that the problem may have been modified a bit at some point and the answer key not updated.
 
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Excuse me this question is from which country?
 
I am from the US. This question is from Engineering Circuit Analysis 8th Edition, by William H. Hayt Jr.
 

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