Step-by-Step Guide to Solving Differential Equations | Expert Tips and Tricks

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A user sought help with solving a differential equation related to circuit analysis but struggled to reach the provided answer. They attempted various methods, including loop analysis and node analysis, but found their results differed from the expected outcome. Other users suggested simplifying the problem using impedance and provided encouragement to share their work for better assistance. Ultimately, the original poster successfully solved the problem after multiple attempts and expressed gratitude, indicating they would share their solution for others' benefit. The discussion highlights the collaborative nature of problem-solving in complex subjects like differential equations.
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Hi ,
Can anyone help me on this problem please?!
Answer is given but i want to know steps to come to it, i think i tried a lot to solve it but i couldn't come to the given result.
Thanks to all
 

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hi xmenus! welcome to pf! :wink:

show us what you've tried, and where you're stuck, and then we'll know how to help! :smile:
 
Here's the link of doc..I think i tried loop method and many other forms but... here i just showed the analogy i tried but i couldn't come to the result.(First circuit is different one)
I took an other example just to show or ask if the other circuit can be solved with the same analogy?!

https://www.dropbox.com/sh/7g4vmpl4uhjbyl4/wwNdGrKm5o
 
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it's rather difficult to read :redface:

anyway, what is D ? :confused:
 
That's a tough circuit you posted for finding a differential equation.

Don't know for sure...but perhaps a node analysis on the upper right hand node? Current in equal current out sort of thing.

Using SL and 1/(SC) may simplify things as well.
 
xmenus said:
I took an other example just to show or ask if the other circuit can be solved with the same analogy?!

ah, D = d/dt !

ok, you've replaced C and R3 (in series) by an impedance Z1

(btw, wouldn't Z3 be an easier name to keep track of? :wink:)

then you've replaced R2 and Z1 (in parallel) by Ze

but then you've stopped (presumably you're going to replace L and Ze, then replace that and R1?)

well, that looks fine so far :smile:

what's the difficulty?​
 
The problem is that it's not working like that.I can't come to the result, i don't know!?
 
but you stopped, you only got as far as Ze :confused:
 
  • #10
No,actually i worked on it till to the end but the result i got is not like the given one.
You are right, i didnt post other steps,but on that way it didnt work!
 
  • #11
we can't comment on why it didn't work unless you show us what you did
 
  • #12
Finally,after many attempts, i solved it :D !

I might post the solution so anyone can find it useful maybe.
Thank you a lot anyway,and thank for your time!
 
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  • #13
Solution is in .pdf file.

Regards
 

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