Step up transformer + ac generator question

In summary: The ratio of the voltages should be equal to the ratio of the number of coils. So in this case, the secondary voltage is 340V and the primary voltage is 155V. This gives us a ratio of 340/155. We know that the frequency is changing from 60Hz to 50Hz, so we also need to take that into account. The equation is set up like this: 340/155 = No. of coils on secondary / No. of coils on primary We are solving for the number of coils on the secondary, so we can rearrange the equation to isolate that variable: No. of coils on secondary = (340/155) * No. of coils on primary Now we
  • #1
tobz102
2
0

Homework Statement


An AC generator, originally designed to provide a peak output of +/- 155V at frequency 60Hz, is required to provide a peak output of +/- 340V at 50Hz. If the generator is connected to a transformer with 200 loops in its primary coil, how many loops should there be in the secondary coil in order to required the output?


Homework Equations


transformer equation? EMF on secondary / EMF on primary = No. coils on secondary / No. coils on primary


The Attempt at a Solution


I don't understand where to start on this? I know that I need to use the above equation but unsure how to get there
 
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  • #2
Break it down to what is happening at the primary (input) and secondary (output)

Primary

Voltage =?
No. of coils = ?

Secondary

Voltage =?
No. of coils = ?
 
  • #3
rock.freak667 said:
Break it down to what is happening at the primary (input) and secondary (output)

Primary

Voltage =?
No. of coils = ?

Secondary

Voltage =?
No. of coils = ?

I was thinking along the lines of:

Primary V=155V
Coils = 200 loops

Secondary V=340V
Coils=?

But surely this is too much of a simple method and also it gets me the frequency of the a.c current...
 
  • #4
tobz102 said:
I was thinking along the lines of:

Primary V=155V
Coils = 200 loops

Secondary V=340V
Coils=?

But surely this is too much of a simple method and also it gets me the frequency of the a.c current...

Well using the transformer equation that is how it should be done.
 
  • #5
.

I would approach this problem by first understanding the basic principles behind transformers and AC generators. A transformer is an electrical device that can increase or decrease the voltage of an alternating current (AC) by using two coils, a primary and a secondary, that are connected by a magnetic core. An AC generator, on the other hand, is a device that converts mechanical energy into electrical energy by rotating a coil in a magnetic field.

In this scenario, the AC generator is designed to provide a peak output of +/- 155V at a frequency of 60Hz. This means that the voltage of the AC output fluctuates between +155V and -155V, with a frequency of 60 cycles per second. However, the requirement is to increase the peak output to +/- 340V at a frequency of 50Hz. This means that the voltage of the AC output will now fluctuate between +340V and -340V, with a frequency of 50 cycles per second.

To achieve this, we can use a step-up transformer, which will increase the voltage of the AC output. The transformer equation, as mentioned in the problem statement, is EMF on secondary / EMF on primary = No. coils on secondary / No. coils on primary. This equation tells us that the ratio of the number of coils in the secondary (Ns) to the number of coils in the primary (Np) is equal to the ratio of the EMF (electromotive force) on the secondary (Vs) to the EMF on the primary (Vp).

In this problem, we know the voltage and frequency of the AC output from the generator, and we need to determine the number of coils in the secondary to achieve the desired output. We can rearrange the transformer equation to solve for Ns:

Ns = (Vs/Vp) * Np

Substituting the known values, we get:

Ns = (340V/155V) * 200 = 436.77

Therefore, the secondary coil should have approximately 437 loops to achieve the required output of +/- 340V at 50Hz. However, it is important to note that this is an ideal calculation and does not take into account losses in the transformer and generator. In reality, the number of coils in the secondary may need to be slightly higher to compensate for these losses.

In conclusion, by understanding the principles of transformers and AC generators, and using the transformer equation
 

1. What is a step-up transformer and how does it work?

A step-up transformer is a device that increases the voltage of an alternating current (AC) electricity supply. It works by using two coils of wire, known as the primary and secondary coils, which are wrapped around an iron core. When an AC current flows through the primary coil, it creates a changing magnetic field which induces a voltage in the secondary coil, resulting in a higher output voltage.

2. What is the purpose of a step-up transformer in an AC generator?

The purpose of a step-up transformer in an AC generator is to increase the voltage of the electricity produced by the generator. This is necessary for transmitting electricity over long distances, as higher voltages experience less energy loss during transmission.

3. How is the voltage ratio determined in a step-up transformer?

The voltage ratio in a step-up transformer is determined by the ratio of the number of turns in the primary and secondary coils. For example, if the primary coil has 100 turns and the secondary coil has 200 turns, the voltage ratio would be 2:1, meaning the output voltage would be twice the input voltage.

4. Can a step-up transformer only increase voltage?

Yes, a step-up transformer is designed to only increase voltage. This is due to the physical properties of the transformer, as the number of turns in the secondary coil must be greater than the primary coil in order for the voltage to be increased.

5. What are some common applications of step-up transformers?

Step-up transformers are commonly used in power transmission systems, where electricity is generated at power plants and then transmitted at high voltages over long distances. They are also used in electronic devices such as televisions and computers, as well as in medical equipment like X-ray machines where high voltages are necessary.

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