Straight line equation easy question

sameh1
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i have an easy question i Know how to calculate the slope but how I can get all the equation I know before that the equation is -2x+2 I know how to calculate the slope it
is y2-y1/x2-x1 but how can I get +2
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The constant is the same as the point where the line crosses the y-axis. So in this case you see it crosses at positive 2 so the constant will be +2.
 
your question is somewhat confusing...if you are asking how to get a slope = 2, you need a different line. the slope of a straight line is constant. y = -2x +2 is a straight line and you calculated the slope correctly, -2.

To find a line with slope = 2, use slope equation...y=mx+b.
 
It's not confusing if you look at the picture
 

Thread 'Finding the nth roots of a complex number'

There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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