Stress and Strain Factor of Safety

AI Thread Summary
To determine the maximum permissible load for a round steel rod with an ultimate strength of 560MPa and a required factor of safety of 6, the calculation involves first converting the diameter into meters to find the cross-sectional area. The maximum load can be calculated by multiplying the allowable stress (ultimate strength divided by the factor of safety) by the cross-sectional area. For the steel hanger supporting a load of 71000N, the factor of safety can be found by dividing the ultimate strength by the actual stress (load divided by cross-sectional area). Converting units from cm² to m² and MPa to Pa is essential for accurate calculations. Understanding the relationship between maximum stress and ultimate stress is crucial for solving these problems effectively.
nettie2311
Messages
14
Reaction score
0

Homework Statement





Hello,

I've been given a question:

The ultimate strength of a round steel rod is 560MPa. If a factor of safety is 6 is required, what is the maximum permissible load for the rod if it has a diameter of 6.9cm?

If anyone can explain how to set up this calculation and how I go about solving this question it would be great.
 
Physics news on Phys.org

Homework Statement



Hello,

I have been given the question:

What is the factor of safety of a steel hanger having an ultimate strength of 560MPa and supporting a load of 71000N. The steel hanger in question has a cross sectional area of 5 cm squared.

If anyone can help me set up the formula and explain how I go about solving this question that would be great.
 
Hello,

Thanks for the reply...I've tried calculating it and I'm pretty close but for some reason a few decimal places off.

I'm guessing I need to convert cm squared to metre squared? And MPa to Pa? I'm getting all confused.
 
Start with the definition of the factor of safety, how does it relate the maximum stress to the ultimate stress?
 
Back
Top