Stuck on a Torque Problem Help is appreciated

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A 45.5kg mass is attached to a light string wrapped around a cylindrical spool with a radius of 10cm and a moment of inertia of 4.0kg*m^2, and it is released from a height of 3.5m. To solve for the time it takes to reach the floor, the sum of the torques must equal the moment of inertia multiplied by the angular acceleration. The downward acceleration of the mass is related to the rotational acceleration of the spool, which complicates the calculation. It is essential to focus on finding the angular acceleration (α) rather than the angular velocity (ω) and to draw a free body diagram (FBD) for better visualization. Ultimately, the problem requires using the SUVAT equations to find the time based on the calculated acceleration.
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Stuck on a Torque Problem! Help is appreciated!

1. A mass of 45.5kg is attached to a light string (negligible) that is wrapped around a cylindrical spool of radius 10cm and moment of inertia 4.0kg*m^2. The spool is suspended from the ceiling, and the mass is then released from rest a distance 3.5m above the floor. How long does it take to reach the floor?
2. Sum of the torques = Inertia * angular acceleration
3. I calculated the mass of the spool to be 400kg by using I=mr^2. After that, I'm directionless! Thanks in advance for your help :)
 
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Distance is given and you are required to find time.
You can use SUVAT equation to find the time.
Another value you need to find is the accceleration.
Downward acceleration of the mass is also related to rotational acceleration of the spool.
 


that helps a bit but I'm still confused on how to calculate angular acceleration since i don't know ω...
 


cngest said:
that helps a bit but I'm still confused on how to calculate angular acceleration since i don't know ω...

You have find α not ω.
Just assume downward acceleration equal to a.
Then draw a fbd of the mass.

Assume a force is pulling 2 bodies connected by a string. But here the second body is a spool.
 
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