- #1
wisredz
- 111
- 0
can't get this!
Hi there,
I have a question that I cannot solve. Here it is.
[tex]\frac{1}{\sqrt(4-2\sqrt3)}=x+y\sqrt3 [/tex]
then what is x^2+y^2?
All I did was finding what left hand side stood for. It equals
[tex]\frac{\sqrt3 + 1}{2} [/tex]
Any help?
Hi there,
I have a question that I cannot solve. Here it is.
[tex]\frac{1}{\sqrt(4-2\sqrt3)}=x+y\sqrt3 [/tex]
then what is x^2+y^2?
All I did was finding what left hand side stood for. It equals
[tex]\frac{\sqrt3 + 1}{2} [/tex]
Any help?