- #1

rms5643

- 20

- 0

## Homework Statement

Use mesh analysis to find the power delivered by the current-controlled voltage source in the circuit in the Figure: http://i.imgur.com/LUXYFO5.jpg

## Homework Equations

1 super mesh equation, 1 source equation, 1 mesh equation, KVL

## The Attempt at a Solution

To start off, I made all of my currents flow counter-clockwise and I labeled them, starting from the bottom left loop, then bottom right, then upper left, then upper right loop as: W, X, Y & Z, respectively.

Next, I drew a super mesh equation around Y and Z (Upper left and upper right). My super mesh equation:

6*Y-X+8*Z=0

Next, I wrote down my source equation:

3=Z-Y

Finally, I did a regular loop around X (Bottom right):

6*X+X+32*(X+W/8)=0 (Note, I added W/8 instead of subtracted because I defined all my currents to go counter-clockwise, except, the current coming from the voltage-controlled current source is going the opposite way, so it would technically be 32*(X-(-W/8)). I'm not sure if this assumption is correct. I think my mistake may be there.

Next, since W is an unknown, I need one more equation. Since W is defined as the voltage drop across the upper left resistor, I wrote the following:

W=6*Y

Now, here I am also unsure whether or not this is correct. Since Y is entering the negative terminal of the resistor, or at least I've defined it to be, would that make W=6*-Y?

So, my two questions are whether W/8 is positive or negative in 6*X+X+32*(X(+/-)W/8) and whether Y should be negative or positive in W=6*(+/-)Y. (As well as my mesh loops, not quite sure I completely have the hang of mesh analysis)

Thanks for all of your help again!