Superposition Method for Finding Vout: Steps and Equations Explained

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The discussion focuses on using the superposition method to find output voltage (Vout) in a circuit analysis problem. The user successfully calculated Vout1 by shorting the voltage source, yielding a result of 0.85V, but is confused about finding Vout2 after opening the current source. Clarifications are provided on how to redraw the circuit without the current source and to apply Kirchhoff's Voltage Law (KVL) and Kirchhoff's Current Law (KCL) for further analysis. There is also skepticism about the necessity of using superposition for this particular circuit. Understanding the circuit configuration and applying the correct analysis methods are emphasized as crucial steps.
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Homework Statement



See pdf attachment named Superposition .Find Vout

Homework Equations



Steps of Superposition

The Attempt at a Solution



I fount Vout1 by replacing the voltage source with a short circuit and doing basic d.c. analysis. My answer = 0.85V

However I'm stuck on how to find Vout2. I know you have to replace the current source with an open circuit. This however confuses me as there is now an open circuit in the middle of my circuit and I'm unsure what resistors, if any are in parallel and how to find the voltage across the load which is Vout2

Any help is greatly appreciated.

Thanks
 

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I am not sure which V you are talking about. That network is really confusing to look at.

Could you maybe post your calculations for how you found Vout1 so I can tell where you are coming from?

However I'm stuck on how to find Vout2. I know you have to replace the current source with an open circuit. This however confuses me as there is now an open circuit in the middle of my circuit and I'm unsure what resistors, if any are in parallel and how to find the voltage across the load which is Vout2

So, for superposition, you know that you short Vsources and open Isources.

Now, you say that you are confused because there would be an open circuit in the middle of the circuit?

Well, that's not completely true. You would be "opening" the current source, which means you just re-draw the circuit without the current source and perform your analysis again.

Since all you have left is a Vsource, I would recommend using KVL to find all of the currents. That's a hint that you should use KCL to find all of the voltages.

The more I look at the circuit, I wonder why you are using superposition anyway?
 

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