Support Function for Set of Points in $\mathbb{R}^2$

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Homework Statement


Let ##\left\{(x_1,x_2) \in \mathbb{R}^2: 0 \leq x_1 \leq 1 \; \text{and} \; 0 \leq x_2 \leq 1\right\}.## Find the support function ##\mu_s## for this set.

Homework Equations


We define the support function ##\mu_s: \mathbb{R}^n \rightarrow \mathbb{R} \cup \left\{-\infty\right\}## as ##\mu_s(p) = \inf\left\{p \cdot x: x \in S\right\}##.

The Attempt at a Solution


I know this is a square with vertices at ##(0,0)##, ##(0,1)##, ##(1,0)## and ##(1,1)##. I'll take a line that goes through ##(0,1)## and take a vector ##p## that is orthogonal to this. I get stuck after this in finding the support function

Someone please help!.
 
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I think you need to find the maximum size of a vector in S, since the infimum of the dot product of p with an element x in S will be ## -|p| max_{x \in S}( |x| )##.
 
Thanks. Here we are basically trying to maximise ##p_1x_1+p_2x_2## subject to the constraint ##p_1 \geq 0## and ##p_2 \leq 1.## The support function is
$$\mu_S(x_1,x_2) = \begin{cases}
x_1+x_2, & \text{if} \; x_1, x_2 \geq 0 \\
x_1, & \text{if} \; x_1 \geq 0, x_2 < 0 \\
x_2, & \text{if} \; x_1 < 0, x_2 \geq 0 \\
0 & \text{otherwise}
\end{cases}.$$
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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