So the first question is to find the surface area of a torus generated by rotating the circle (or shall I say semi circle) y=√r-x(adsbygoogle = window.adsbygoogle || []).push({}); ^{2}around y=r

if the idea is to find the surface are of the half torus and then multiply by 2, wouldn't it be the same for the circle (or shall I say semi circle, again) rotated around x=r???

Thanks.

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# Homework Help: Surface Area of a Torus

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