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Volume enclosed by a torus

  1. Aug 9, 2012 #1
    A torus is generated by rotating the circle x2[/SUP+(y-R)2=r2

    Find the volume enclosed by the torus.


    Well, I don't know what to do! I thought that rewritting it as

    [itex]\sqrt{r2-x2}[/itex]+R

    would help, but im not sure.

    Thanks.

    PD: Is this solid revolutions? because I forgot how to do it...(any refresher????)
     
  2. jcsd
  3. Aug 9, 2012 #2
    For integration parallel with axis of rotation...

    [itex]\Pi \int^b_a [f(x)]^2[/itex]

    for integration perpendicular to axis of rotation...

    [itex]2\Pi \int^b_a xf(x)[/itex]
     
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