Surface Integral: Evaluating zdS in Hyperboloid of Two Sheets

bosox284
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Homework Statement
Evaluate the surface integral, the double integral of zdS if the region is the patch of surface defined by x^2 + y^2 - z^2 = -1 in the first octant with z less than or equal to 4.


The attempt at a solution
I really don't know where to begin. I believe the equation is of a hyperboloid of two sheets. So I want to say I have to parametrize the equation with x = bxcos(u)sinh(v), y = bysin(u)sinh(v), z = bzcosh(v), and then take the partial derivatives of u and v, and take the cross product of the two. Could someone please point me in the right direction? Or instruct me where to go from there?
 
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bosox284 said:
The attempt at a solution
I really don't know where to begin. I believe the equation is of a hyperboloid of two sheets. So I want to say I have to parametrize the equation with x = bxcos(u)sinh(v), y = bysin(u)sinh(v), z = bzcosh(v), and then take the partial derivatives of u and v, and take the cross product of the two. Could someone please point me in the right direction? Or instruct me where to go from there?

That sounds like a good plan, although I see no need for the b's...why not show us how far you get with that method?
 
Well the b's would be for if it were like (x^2)/4, where b would be 2. So in this case, the value of b is one and I could have gone without them. The only problem I see myself running into from here, would probably be finding out the values of u and v for when I set up the integral.
 
That shouldn't be too difficult...x,y, and z all have to be positive in the first octant and z\leq 4...find the range on v first using your limits on z and then see what range of u-values x and y are positive for.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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