Optimizing Switching Frequency for Voltage Output in a Two-System Circuit

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The discussion centers on optimizing the switching frequency for voltage output in a two-system circuit, focusing on the input and output impedances of the systems. Participants emphasize the importance of accurately determining the time constant (τ) and suggest considering the Thevenin equivalent seen by the capacitor, which includes load-side resistors. There are corrections regarding the use of approximation signs in calculations, as the values provided are exact. The conversation highlights the need for careful analysis of circuit components to achieve the desired voltage levels. Overall, the thread provides insights into circuit analysis techniques relevant to the problem at hand.
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Homework Statement


Problem and Diagram stated below
System 2 Input Impedance: 1k ohms
System 1 Output Impedance: 100 ohms
High interpreted as Voltage greater than 2V
Low Interpreted as Voltage less than 0.5V

switchingfreq.png


Homework Equations


Capacitor Charging eqn:
V=Vo(1-e^-t/RC)

Capacitor Discharging eqn:
V=Voe^-t/RC

f=1/T

The Attempt at a Solution


Posted Below

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Scan0010.jpg

Hey guys. This was a problem given to us on one of our assignments and that was my suggested solution...was wondering if what I did was correct.

Thanks in advance :D
 

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Long story ! Some comments:

First thing that comes to mind for me is the ##\tau## : you sure it's from the 100 Ω only and not the 110 Ω ? (test: let Rin = 1M Ω !)

Second: no need for the ##\approx.## sign. Everything is given 'exactly'. Idem for increasing the 2 * 11/10 to 2.3 and decreasing the 0.5 * 11/10

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As BvU points out, you need to take a closer look at how you determine ##\tau##. Suggestion: find the Thevenin equivalent that the capacitor sees. Note that this will include the load-side resistors too!
 
Good thing gn is on the lookout ! I had forgotten those load side guys. Rustiness...
 

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