Sylow's Theorem Proof for Group of Order 35^3 | Validity Check

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Homework Statement



Show that any group of order 35^3 has a normal subgroup of order 125.


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The Attempt at a Solution



Is this a valid proof?


Let G be an arbitrary group of order 353. Note that 353 = 5373. Thus, by Sylow's first theorem, there is a sylow p-subgroup of order 125, which we refer to as H. But then, by Sylow's second theorem, it follows that H is conjugate to itself in G. Hence, H is normal in G.
 
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I believe you are on the right track, however, I believe you have made an assumption. Sylow's second theorem says that all the Sylow 5-subgroups are conjugate to each other. This does imply normality of H iff H is the only Sylow 5-subgroup of G. I think you can use Sylow's third theorem to show that H is the only Sylow 5-subgroup.
 
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