Trigonometric Half Angle Formula Explained and Applied

  • Thread starter Thread starter jrjack
  • Start date Start date
AI Thread Summary
The discussion revolves around solving the expression tan(1/2 arcsin(-7/25) using the half-angle formula. Initially, the user struggles with the concept of halving the arcsin value and attempts various methods to find the tangent. After several calculations and corrections, the user realizes the correct approach leads to an answer of -1/7. The importance of using a calculator for verification is emphasized, highlighting its utility in checking solutions. Ultimately, the conversation illustrates the process of applying trigonometric identities and the significance of accuracy in calculations.
jrjack
Messages
111
Reaction score
0

Homework Statement



\tan[\frac{1}{2} \arcsin(\frac{-7}{25})]

The Attempt at a Solution



I'm not sure how to take 1/2 the arcsin, should this use the half-angle formula?

Normally I would draw a triangle using the sin value (-7/25), then find the tan value (24/25), but the 1/2 is throwing me off.

How do I start this? Is this 1/2 the sin value (-7/25)= -7/50, then solve for the tan(-7/50)?
 
Physics news on Phys.org
Use the tangent half angle formula. tan(x/2)=??
 
Thanks, so i get

-\sqrt{26}

Does that sound right?
 
jrjack said:
Thanks, so i get

-\sqrt{26}

Does that sound right?

arcsin(-7/25) is about -0.3. If you take half of that and take the tangent, it's nowhere near -sqrt(26) which is about -5. Is it? You can check these solutions using rough estimates or a calculator.
 
-\sqrt{\frac{1+\cos x}{1-\cos x}}
-\sqrt{\frac{1+\frac{24}{25}}{1-\frac{24}{25}}}
=-\sqrt{26}
 
jrjack said:
-\sqrt{\frac{1+\cos x}{1-\cos x}}
-\sqrt{\frac{1+\frac{24}{25}}{1-\frac{24}{25}}}
=-\sqrt{26}

tan(0/2)=0. If you put x=0 into your supposed half angle formula, what do you get? Does it work?
 
Sorry, I now realize I have my signs flipped in my formula.
I think my answer should be:-\sqrt{\frac{1}{26}}
 
jrjack said:
Sorry, I now realize I have my signs flipped in my formula.
I think my answer should be:-\sqrt{\frac{1}{26}}

That doesn't work either because (1-24/25)/(1+24/25) isn't equal to 1/26. Now what's it really equal to??
 
Sorry, I got in a hurry, between typing the tex and working the problem several different ways (wrong of course).

It should equal 1/49, which means my answer should be -\sqrt{\frac{1}{49}}
 
  • #10
jrjack said:
Sorry, I got in a hurry, between typing the tex and working the problem several different ways (wrong of course).

It should equal 1/49, which means my answer should be -\sqrt{\frac{1}{49}}

Ok, aside from the fact there is a simpler way to write -1/sqrt(49) could you try and check that using a calculator from your original expression? It's really useful to have a simple way of self-checking whether you are way off or not.
 
  • #11
Thank you for your help.
I realize I still need to rationalize the denominator, and after checking with my calculator both answers come out to -.142857, so that must be correct.

My final answer should be -1/7

Once again, thank you for your help.
 
  • #12
jrjack said:
Thank you for your help.
I realize I still need to rationalize the denominator, and after checking with my calculator both answers come out to -.142857, so that must be correct.

My final answer should be -1/7

Once again, thank you for your help.

Very welcome and quite right. The main lesson is how easy these answers are to check with a calculator.
 

Similar threads

Back
Top