Tangent line to path

1. Sep 15, 2008

rgalvan2

Find an equation for the line tangent to the given path at the indicated value for the parameter.

x(t)=4costi-3sintj+5tk, t=$$\pi$$/3

So what I did here was take x'(t) and then plugged in $$\pi$$/3 after that to get an equation containing i, j, and k.
x'(t)= -4sinti-3costj+5k
x'($$\pi$$/3)=-4$$\sqrt{3}$$/2i-3/2j+5k
Am I doing this right? Calc III is confusing me so much. Any help would be appreciated. This is due Thursday. Thanks!

2. Sep 15, 2008

Dick

Looks all right so far.

3. Sep 15, 2008

rgalvan2

Alright sweet thanks a lot!